Find the surface area of this prism. Leave your answer as a mixed number in simplest form.
1 answer:
You might be interested in
Y+4<u><</u>9
subtract 4
y<u><</u>5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)
6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)
-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )
I have included pictures of the number lines
subtract 4
y<u><</u>5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)
6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)
-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )
I have included pictures of the number lines
The amount of paint is the volume of paint needed.
The amount of paint needed is 0.065312 cubic meters
<h3>How to determine the amount of paint needed</h3>The volume of a hemisphere is:
Differentiate the above equation
The above equation represents the estimate of the amount of paint needed.
Where:
- r represents the radius (r = 52/2 m)
- r' represents the thickness (r' = 0.04 cm)
So, we have:
Express cm as m
Hence, the amount of paint needed is 0.065312 cubic meters
Read more about volumes at:
Answer:
option C
c. least: $101
greatest: $1001
Step-by-step explanation:
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.
Sum of 10 prizes = 5510
100 is the difference. there is a common difference d=100
So its a arithmetic sequence
the sum formula for arithmetic sequence is
Sn = 5510, n=10 n d= 100 we need to find out first term a1
5510 = 5 (2a1 + 900)
5510 = 10a1 + 4500
Subtract 4500 on both sides
1010= 10a1
divide by 10 on both sides
a1 = 101
so first term that is least term is 101
To find out greatest term we use formula
a(10) = 101 + (10-1)100
= 101 + 900= 1001
greatest is 1001