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3 years ago

Can someone please help.

Mathematics

1 answer:

damaskus [11]3 years ago

8 0

Answer: part A: every month jim deposits $20, so every month his total balance will increase by 20$ starting from $150

Part B: The pattern is 1x for every 9y

Step-by-step explanation:

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Abby uses base 10 blocks to show 1,109. She has no thousands cubes and only 9 flats, as shown. Draw longs and units on the chart

Vinvika [58]

Answer:

20 longs, 9 units more than the 9 flats

Step-by-step explanation:

If Abby has 9 flats, she has 900 blocks of the 1109 she needs. The remaining 209 can be represented by ...

20 longs

9 units

_____

<em>Comment on the question</em>

We cannot see the model Abby has put together so far, so we don't know exactly what it takes to finish it. Any longs or units she already shows must be subtracted from the numbers above.

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2 years ago

Cora is using successive approximations to estimate a positive solution to

Advocard [28]

Um...... what......?

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3 years ago

Find the value of x. 6 8 4 x

snow_tiger [21]

Answer:

3

Explanation:

4 is half of 8 on the right side, so that means X has to be half of 6, so it’s 3. Also, it couldn’t be 2 because it is too big, and it can’t be 4 because it isn’t the same length as the other 4, so it’s 3

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2 years ago

Line A passes through the points (1, -1) and (-2, 8).

Viefleur [7K]

The answer to this question will be D

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2 years ago

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$