So for this, we will be using dimensional analysis:
In short, he should receive ¥8835.30.
<u>Answer-</u>
<em>The lines are two </em><em>coinciding lines</em><em> or the </em><em>same lines</em><em>.</em>
<u>Solution-</u>
The given line equations are
the first one,
the second one,
As we know two line equations 
and 
will be,
- Parallel if,
- Coincide if,
- Intersect if,
As here,
(C₁ and C₂ aren't considered as they are 0)
Therefore, the lines are two coinciding lines or the same lines.
Answer: Since her art and music sections each only had half the number of sheets of paper as a core subject, together the two sections had the same amount of paper as a core subject. Therefore, it is almost like her notebook had five core subjects, rather than four core subjects and two electives. If she divided the 200 sheets equally among the five core subjects, there would be 200 ÷ 5 = 40 sheets in each section. Now we can see that art would actually have half of this amount, or 20 sheets of paper.
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
