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alexdok [17]
2 years ago
5

What type of number is 2?

Mathematics
2 answers:
gizmo_the_mogwai [7]2 years ago
8 0
Number 2 is a real number
Trava [24]2 years ago
4 0

Answer:

real

Step-by-step explanation:

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PLEASE HELP
lisabon 2012 [21]

Answer:

Step-by-step explanation:

5 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Help me plzplzplzplz1
mezya [45]

Answer:

The answer is 400 when you round it off to the nearest hundred.

4 0
3 years ago
Find the slope (-8,10) (8,15)
Novosadov [1.4K]
<h3>Question:</h3>

find the slope (-8,10) (8,15)

<h3>Answer:</h3>

m = \frac{5}{16}

<h3>Step-by-step explanation:</h3>

Use the slope formula \frac{y2-y1}{x2-x1}

(x2,y1) = (-8,10) , (x2,y2) = (8,15)

m = \frac{15-10}{8-(-8)}

m = \frac{5}{16}

Hope this helps :)

Please consider marking my answer brainlist!

7 0
3 years ago
F(x) = 4x^2+5x-12 evaluate f(-3)
Natali5045456 [20]
F(-3)=4(-3)^2+5(-3)-12
=36-15-12
=36-27
=-9
4 0
3 years ago
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