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Bess [88]
3 years ago
12

Same solution as 2(x+4=-7-3x

Mathematics
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

x = -3

Step-by-step explanation:

2(x+4)=-7-3x

Distribute

2x+8 = -7-3x

Add 3x to each side

2x+3x+8=-7-3x+3x

5x +8 = -7

Subtract 8 from each side

5x+8-8 = -7-8

5x = -15

Divide each side by 5

5x/5 = -15/5

x = -3

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3 years ago
What is the partial fraction decomposition of StartFraction 8 x + 19 Over (x + 8) (x minus 1) EndFraction? StartFraction 3 Over
hoa [83]

The partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

<h3>How to determine the decomposition?</h3>

The fraction is given as:

\frac{8x + 19}{(x + 8)(x - 1)}

Split the fraction as follows:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}

Take the LCM

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}

Cancel the common factors

8x + 19 = Ax - A + Bx + 8B

By comparison, we have:

Ax + Bx = 8x

-A + 8B = 19

This gives

A + B = 8

-A + 8B = 19

Add both equations

9B = 27

Divide by 9

B = 3

Substitute B = 3 in A + B = 8

A + 3 = 8

Solve for A

A = 5

So, we have:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Hence, the partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Read more about partial fraction at:

brainly.com/question/12783868

#SPJ1

6 0
2 years ago
If I have (-2, 7) and (6, y) distancia = 10 . How can I find y?
shusha [124]

Answer:

y = 13

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 2, 7) and (x₂, y₂ ) = (6, y)

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64 + (y - 7)² = 100 ( subtract 64 from both sides )

(y - 7)² = 36 ← take the square root of both sides

y - 7 = 6 ( add 7 to both sides )

y = 13

7 0
3 years ago
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