<span>There are 100 possible pairs of numbers.
Half of them start with an even number so only 50 have a first odd number.
Of those remaining 50, half of those have an odd second number.
Leaving 25 of the original 100 to have two odd numbers.
P= 25/100=1/4</span>
Answer:
The father is 50 and his son is 15.
Step-by-step explanation:
Double the tens digit of the father's age = 10
Plus 5 = 15 (the age of the son)
50 + 15 = 65 (the sum of their ages)
The reverse of the digits of the son's age is 51.
Subtract 1 = 50 (the age of the father)
Not enough info
i need more info
que?
