Answer:
The point slope form of required line is
.
Step-by-step explanation:
It is given the the required line passes through the point (6,1) and perpendicular to a line with a slope of -3.
The product of slopes of two perpendicular lines is -1.
Let the slope of required line be m.
![m\times -3=-1](https://tex.z-dn.net/?f=m%5Ctimes%20-3%3D-1)
Divide both sides by -3.
![m=\frac{-1}{-3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-1%7D%7B-3%7D)
![m=\frac{1}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B1%7D%7B3%7D)
The slope of required line is 1/3.
If a line passes through the point
with sloe m, then the point slope form of the line is
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
The point slope form of required line is
![y-1=\frac{1}{3}(x-6)](https://tex.z-dn.net/?f=y-1%3D%5Cfrac%7B1%7D%7B3%7D%28x-6%29)
Therefore the point slope form of required line is
.