Question

Given that $A = (\sqrt{2008}+\sqrt{2009}),$ $B = (-\sqrt{2008}-\sqrt{2009}),$ $C = (\sqrt{2008}-\sqrt{2009}),$ and $D = (\sqrt{2009}-\sqrt{2008}),$ find $ABCD.$

Answer 1

Answer:

ABCD = 0.803

Step-by-step explanation:

$A = \sqrt{2008}+\sqrt{2009} \\A = 44.81 + 44.82\\A = 89.63$

$B = -\sqrt{2008}-\sqrt{2009}\\B = -44.81 - 44.82\\B = -89.63$

$C = \sqrt{2008}-\sqrt{2009}\\C = 44.81 - 44.82\\C = - 0.01$

$D = \sqrt{2009}-\sqrt{2008}\\D = 44.82 - 44.81\\D = 0.01$

ABCD = 89.63 * (-89.63) * (-0.01) * (0.01)

ABCD = 0.803