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Phantasy [73]
3 years ago
14

Please help!!

Mathematics
2 answers:
Step2247 [10]3 years ago
8 0
Complete the square to get the equation in vertex form with 
a<span> = -16, </span>h<span> = 1, and </span>k<span> = 19. The path is a reflection over the </span>x<span>-axis and narrower. It is also translated right 1 unit and up 19 units.</span>
Tanya [424]3 years ago
8 0

Answer:

Exactly right

Step-by-step explanation:


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Simplify each expression.
Ivenika [448]

Answer:


-13n+21 if i did it properly.


4 0
3 years ago
Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4
Vladimir79 [104]

Answer:

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3) ⇒ 2nd

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is 32y^{10}-24

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ 32y^{10}-24 = 8(  y^{10}-3)  ⇒ the same with the answer

∴ The expression 32y^{10}-24 = 8(y^{10}-3) is completely factored

∵ The expression is 20y^{7}+10y^{2}

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of y^{7} and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ 20y^{7}+10y^{2}=10y^{2}(2y^{5}+1) ⇒ not the same with the answer

∵ The expression is 16y^{5}+12y^{3}

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of y^{5} and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ the same with the answer

∴ The expression 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) is completely factored

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3)

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)

3 0
3 years ago
Evaluate each function.<br> w(a)= a + 4; Find w(1)
Anuta_ua [19.1K]

Answer: 5

because w(a) = a + 4

=> w(1) = 1+ 4 = 5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If $450 is invested at 6% compounded A (annually), B (quarterly), C (monthly), what is the amount after 7 years? How much intere
ss7ja [257]

Answer:

Step-by-step explanation:

Here's the gameplan for this.  First of all we need a general formula, then we will define the variables for each.

The general formula for all of these is the same:

A(t)=P(1+\frac{r}{n})^{nt}

where A(t) is the amount after the compounding, P is the initial investment, n is the number of compoundings per year, r is the interest rate in decimal form, and t is time in years.  

Then after we find the amount after the compounding, we will subtract the initial amount from that, because the amount at the end of the compounding is greater than the initial amount.  It's greater because it represents the initial amount PLUS the interest earned.  The difference between the initial amount and the amount at the end is the interest earned.

For A:

A(t) = ?

P = 450

n = 1

r = .06

t = 7

A(t)=450(1+\frac{.06}{1})^{(1)(7)}

Simplifying gives us

A(t)=450(1.06)^7

Raise 1.06 to the 7th power and then multiply in the 450 to get that

A(t) = 676.63 and

I = 676.63 - 450

I = 226.63

For B:

A(t) = ?

P = 450

n = 4 (there are 4 quarters in a year)

r = .06

t = 7

A(t)=450(1+\frac{.06}{4})^{(4)(7)}

Simplifying inside the parenthesis and multiplying the exponents together gives us

A(t)=450(1.015)^{28}

Raising 1.015 to the 28th power and then multiplying in the 450 gives us that

A(t) = 682.45

I = 682.45 - 450

I = 232.75

For C:

A(t) = ?

P = 450

n = 12 (there are 12 months in a year)

r = .06

t = 7

A(t)=450(1+\frac{.06}{12})^{(12)(7)}

Simplifying the parenthesis and the exponents:

A(t)=450(1+.005)^{84}

Adding inside the parenthesis and raising to the 84th power and multiplying in 450 gives you that

A(t) = 684.17

I = 684.17 - 450

I = 234.17

4 0
3 years ago
What is the solution to this system of linear equations?
Anarel [89]
9x = 27
x = 3
y = -1
The answer is (3, -1)
3 0
4 years ago
Read 2 more answers
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