So this question is already perfectly set up. Since the 6 and -6 cancel you’ll be left with 5x + 3x which is 8x and -32 + 48 which is 16. 8x=16. Isolate x to get that x=2. Plug 2 back into one of the equations. 5(2) -6y = -32. Solve for y now. -10-32 equals -42. Divide -42 by -6 to get 7. So the final coordinate where the two equations will intersect is (2,7)
Answer:
(2x+3)(5x+2)
Step-by-step explanation:
10x²+19x+6
multiply to get 60
add to get 19
10x²+19x+6
(10x²+15x)(+4x+6)
factorise:
10x²+15x
5x(2x+3)
4x+6
2(2x+3)
(2x+3)(5x+2)
<h3>
Answer: Choice B</h3>
Explanation:
Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.
Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.
Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.
Choice D is ruled out for similar reasoning as choice A. Recall that 
Answer:
Odd integers
Step-by-step explanation:
The range is odd integers, if you add 1 to any even integer it becomes an odd integer. 2+1=3; 10+1=11
Answer:
C 2/3
Step-by-step explanation:
this is because there are three different types of sandwiches and he picks two out of the three.