Answer and Explanation:
Given : The random variable x has the following probability distribution.
To find :
a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.
b. Calculate the expected value of x.
c. Calculate the variance of x.
d. Calculate the standard deviation of x.
Solution :
First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.25 0 0 0
1 0.20 0.20 1 0.20
2 0.15 0.3 4 0.6
3 0.30 0.9 9 2.7
4 0.10 0.4 16 1.6
∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1
a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.


Yes it is a probability distribution.
b) The expected value of x is defined as

c) The variance of x is defined as

d) The standard deviation of x is defined as



Answer:
w ≤ 593
Step-by-step explanation:
Missing option;
w ≥ 593
w > 593
w ≤ 593
593 < w
Explanation:
w ≥ 593 No
Number of wrapping paper sold never be more than 593.
w > 593 no
Number of wrapping paper sold never be more than 593.
w ≤ 593 yes
Number of wrapping paper sold will be equal or less than 593.
Answer:216 is your answer
Step-by-step explanation:
Answer: 32/35
Step-by-step explanation:
got it correct
Answer: 916. Because if you do 856+60=916.
Step-by-step explanation: The standard normal distribution is a normal distribution with a mean of zero and standard deviation of 1. Formula: and natural statistics x and x2. The dual expectation parameters for normal distribution are η1 = μ and η2 = μ2 + σ2.