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Ierofanga [76]
3 years ago
8

 A student has a​ one-dollar bill, a​ five-dollar bill, and a​ ten-dollar bill in a box. The student selects a bill from the box

48 times and selects the one dash dollar bill 11 times. What formula should be used to calculate the experimental​ probability? What is the experimental probability of selecting the one dash dollar ​bill? What is the theoretical probability of selecting the one dash dollar ​bill?
Mathematics
1 answer:
viva [34]3 years ago
4 0

Answer:

r/n

22.91%

33.33%

Step-by-step explanation:

To calculate the experimental probability, we must divide the number of times the event occurred by the total number of events, that is:

r / n

r = 11, n = 48

11/48 = 0.2291

In other words, the experimental probability is 22.91%

for the theoretical probability it would be the quantity that there is of that object among the total quantity of objects, in this case it would be:

1/3 = 0.3333

that is, the probability is 33.33%

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Answer:

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Step-by-step explanation:

If the worker is descending, he is going down. The change in his position could be marked on a graph by translating the original point down by 60 units. Aka -60 units.

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3 years ago
PLZ HELP, GIVING BRAINLIEST!
mote1985 [20]

Answer:

  d)  (-3/2, -1/2)

Step-by-step explanation:

The midpoint (M) between two given points is the average of their coordinate values:

  M = (A + B)/2 = ((-8, 1) +(5, -2))/2 = (-3, -1)/2

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Answer:

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Brainliest and 30 points please help
kolbaska11 [484]

Answer:

22. Perimeter = 52 units

     Area = 160 Square Units

23. Notation form :  2 \times 10^{5}

     Standard Form : 200000

Step-by-step explanation:

22.

The formula for perimeter is

P = 2 (length + Width )

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  =  2(5x+1)

The Formula for Area of a rectangle is

A= length x width

A= 2x \times (3x+1)

A=6x^2+2x

Now we have to find the Perimeter and Area for x = 5

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23.

A. By using rule of exponents , we can determine that both the results will be same.

B.

Miriam's calculation

\frac{2.8 \times 10^{9}}{1.4 \times 10^{4}}

\frac{2.8}{1.4} \times 10^{9-4}

2 \times 10^5

Priya's calculation

\frac{2.8 \times 10^{2}}{1.4 \times 10^{-3}}

\frac{2.8}{1.4} \times 10^{2-(-3)}

2 \times 10^5

Standard notation

2 \times 10^5 = 200000

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