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2 years ago

Х 3х+8 Find the value of x

Mathematics

2 answers:

trapecia [35]2 years ago

4 0

Answer:

x=2 $\frac{2}{3}$

Step-by-step explanation:

divide both size by 3

⇒ $\frac{3x}{3}$ = $\frac{8}{3}$

3 will cancel 3x then x will stand on it own

x= $\frac{8}{3}$

3 will divide 8

x=2 $\frac{2}{3}$

joja [24]2 years ago

3 0

The answer is -8/3. first you set it equal to zero, subtract 8 from both sides you get 3x=-8, divide both sides by 3 and you get -8/3

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What solution is <br> y=9x+35<br> y=-8/9x+4/5

Ainat [17]

Answer:

x=-1539/445, y=1724/445. (-1539/445, 1724/445).

Step-by-step explanation:

y=9x+35

y=-8/9x+4/5

-------------------

9x+35=-8/9x+4/5

9x-(-8/9x)=4/5-35

9x+8/9x=4/5-175/5

81/9x+8/9x=-171/5

89/9x=-171/5

x=(-171/5)/(89/9)

x=(-171/5)(9/89)

x=-1539/445

y=9(-1539/445)+35

y=1724/445

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3 years ago

Use the discriminant to find the number of real solutions of the equation 3x^2 – 5x + 4 = 0

Virty [35]

To use the discriminant, first identify a, b, and c. In your equation a= 3 b = -5 and c = 4. Now plug into the discriminant b^2 - 4ac. Substituting yields (-5)^2 - 4(3)(4). Simplifying, 25 - 48 = -23. Since the discriminant has a negative value, there is no real solution to this equation.

4 0

3 years ago

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Find the nth term, a n, of the given arithmetic sequence. a^1 = 75, d = –8, n = 11

kap26 [50]

An = a1+d*(n-1)
a11 = 75-8*(11-1) = -5

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3 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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3 years ago

21 = -3c + 7 -5c -2<br><br>i need help with this multi step equation question

belka [17]

Answer:

c=-2

Step-by-step explanation:

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3 years ago

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