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Anuta_ua [19.1K]
3 years ago
12

PLEASE ANSWER THIS QUESTION,ILL MARK YOU AS THE BRAINLIEST IF UR ANSWER IS CORRECT.

Mathematics
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

I WILL SAY THE 2 ONE

Step-by-step explanation:

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The linear model y equal 0.6 x plus 45 represents the number of pairs of sandals sold, y, for a given outdoor temperature of x d
Alexxx [7]

Answer:

99

Step-by-step explanation:

Given the linear equation:

y = 0.6x + 45

x = outdoor temping degrees ; y = number of pair of sandal sold

Number of pairs of sandals the company expect to sell if the outside temperature is 90 degrees?

y = 0.6(90) + 45

y = 54 + 45

y = 99

The expected number of sandals to sale will be 99

5 0
3 years ago
A dolphin jumped from 5 feet below the surface of the sea. Jane wrote −5 to represent the depth from which the dolphin jumped. W
anzhelika [568]
0 represent the sea surface since the dolphin jumped from five feet below the sea surface and since Jane put that the dolphin jumped at -5 below the sea surface that would mean that 0 must represent the sea surface.
3 0
3 years ago
Given that f (x) = StartFraction 2 Over x squared EndFraction and g (x) = StartFraction 13 Over x squared EndFraction What is th
taurus [48]

The given functions of <em>f </em>and <em>g</em>, where;f(x) =  \frac{2}{ {x}^{2} }, g(x) =  \frac{13}{ {x}^{2} } gives the domain of the functions as the option;

a. All non zero real numbers

<h3>How can the domain of the functions be found?</h3>

The given functions are presented as follows;

f(x) =  \frac{2}{ {x}^{2} }

g(x) =  \frac{13}{ {x}^{2} }

The given functions have <em>x²</em> as the denominator, therefore;

The domain of the functions are the possible x-values, which gives;

x² = (-x)² = Positive number

At <em>x </em>= 0, we have;

f(x) =  \frac{2}{ {0}^{2} }  =  \infty

g(x) =  \frac{13}{ {0}^{2} }  =  \infty

The domain is therefore;

a. All non zero real numbers

Learn more about the domain and range of a function here:

brainly.com/question/2264373

#SPJ1

7 0
1 year ago
Name: cuiusly thens
dlinn [17]

BTW,
KEY:
• exponents are going to be written as “^(x)”.
• if I put “huh” or “nope” or “what” (etc.) that means I don’t know how to solve it.

1. 49a
2.-15x^(2)+2y^(2)
3.-23a+2b+6
4. 0
5.-9c+3d
6. 4a+14b+c
7.-6a+2b+62
8.-3x+8
9. 16x^(2)-y+x+z
10.-6x
11.-8xy+2
12.-15a+3b
13. nah bruh
14. nope
15. 1.5a
16. -10a-2205
17. -4cd+55
18.-4x+2y+3
19. -67,209
20. huh?
21. what??
22. 18a+4b
23. 8y+3x+6
24.-2x+2y+6r+2
25. 4a^(2)+2a+2b+3
7 0
3 years ago
Help, please! 84 points btw
mash [69]
Kriston spend 260 and Ariel 100
8 0
3 years ago
Read 2 more answers
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