Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Answer:
NO because 7+5=12
The sum must be larger (not equal to) the longest side. If it's exactly the same, there's no room to for the shorter two sides to angle up to form a triangle.
OOH, that's tricky--- give a shot first though!
Answer:
answer is the 2nd one
Step-by-step explanation:
y = 1/3(3) - 1 = 1 - 1 = 0 (3,0)
y = 1/3(0) - 1 = 0 - 1 = -1 (0, -1)
y= 1/3(6) - 1 = 2 - 1 = 1 (6, 1)
Step-by-step explanation:
let the ration be c
3x and 4x
Now
3x +4x=24
