What magic trick??
Are you gonna do a magic??
Sorry for a lot of questions.
Answer:
m∠x = 10°
Step-by-step explanation:
Since we are dealing with a <u>right triangle</u> and its two sides and one angle, we can use <u>trigonometry ratios</u>. Remember them all with the acronym SohCahToa.
"o" is for opposite side, "a" is for adjacent side, "h" is for hypotenuse side.
The ratios are:
sinθ = opposite/hypotenuse
cosθ = adjacent/hypotenuse
tanθ = opposite/adjacent
θ means the "angle of reference", or the angle you know or want to find. This determines which side is adjacent (touching) or opposite (not touching). The hypotenuse (longest side) does not change.
In this triangle, θ = x. The sides we know are hypotenuse and opposite. Therefore, we will use the sinθ ratio.
sinθ = opposite/hypotenuse
sinx = CB/AB Substitute the labels in the diagram
sinx = 4/23 Substitute known values (side lengths)
x = sin⁻¹(4/23) Isolate 'x'. Use calculator to solve.
x = 10.015....° Exact answer
x ≈ 10° Round to the nearest degree
Therefore the measure of angle x (m∠x) is 10°.
8 ≥ y + 3 is the answer to problem 7. Also, in problem 5, I couldn't help but notice that the sign should face the other way but still include the equal to sign underneath it, because it should be 4 at MOST, meaning that 4 must be greater than or equal to y + 7.
It's C) -3/4If you need the steps let me know. (:
X= -b over 2a = --6 over 2×1=3
y=3²-6(3)-7=-16
vertex is (3,-16)
axis of symmetry is 3
