Answer:
13
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean Theorem
![a^2+b^2=c^2](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%5E2)
where<em> a</em> and <em>b</em> are the legs and <em>c</em> is the hypotenuse.
We know that the legs are 5 and 12. We also know the hypotenuse is x, or unknown.
Substitute 5 in for <em>a</em>, 12 for <em>b, </em>and x for <em>c.</em>
<em />
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Evaluate the exponents.
5^2 is the same as 5*5, which is 25.
12^2 is the same as 12*12, which is 144.
![25+144=x^2](https://tex.z-dn.net/?f=25%2B144%3Dx%5E2)
Add 25 and 144
![169=x^2](https://tex.z-dn.net/?f=169%3Dx%5E2)
We are trying to find out what <em>x</em> is. In order to do this, we have to get <em>x</em> alone. Since x is being squared, take the square root of both sides. The exponent and square root will cancel, leaving x by itself.
![\sqrt{169} =\sqrt{x^2} \\\\\sqrt{169}=x\\13=x](https://tex.z-dn.net/?f=%5Csqrt%7B169%7D%20%3D%5Csqrt%7Bx%5E2%7D%20%5C%5C%5C%5C%5Csqrt%7B169%7D%3Dx%5C%5C13%3Dx)
The hypotenuse is 13.