It is given in the question that
Point N(7, 4) is translated 5 units up.
And we have to find the coordinates of its image after this transformation.
Since the point translated up by 5 units, so the x coordinate remains same and we have to add 5 to y coordinate.
So the new coordinate after the transformation is
And that's the required coordinate after the given transformation .
Answer:
Step-by-step explanation:
t=(-2.74 + sqrt(2.74^(2)-4*-4.9*(-10))) / -2*-4.9
t=(-2.74 + sqrt(7.5076-4*+49))/9.8
t=(-2.74 + sqrt(7.5076+45))/9.8
t=(-2.74 + sqrt(52.5076))/9.8
t=(-2.74/9.8)+(sqrt(52.5076))/9.8
this is simplest form, next will be rounded answers
t=0.45981763305
She added the numerators
instead of multiplying them
you should also simplify the final answer
the correct answer would be -3 1/8 or -25/8 as an improper fraction.
I think it is 10 because 18×10=180 but it is close hope this helps
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
