Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
Answer:
B
Step-by-step explanation:
edg 2020
Cylinder Volume
V = hπr²
154 cm³ = 16 cm × 3.14 × r²
154 cm³ = 50.28 cm × r²
r² = 154 cm³ : 50.28 cm
r² = 3.0625 cm²
r = 1.75 cm
d = 2r
d = 2 × 1.75 cm
d = 3.5 cm
So, the diameter of the Cylinder is 3.5 cm
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Technically no. It extends forever in the X and Y axis, but does not have a Z axis.
The answer is 96 min, here is why:
x / 240 + x / 160 = 1
<span>2x + 3x = 480 </span>
<span>5x = 480 </span>
<span>x = 96 min
(</span><span>Drainage rate of first pipe = 480000/240 = 2000 l/min </span>
<span>Drainage rate of second tube = 480000/160 = 3000 l/min </span>
<span>Combined drainage rate = 5000 l/min </span>
<span>Time to drain = 480000/5000 = 96 min. )</span>