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3 years ago

11

So I know 5 + 6(2x + 3) - 2x = 10x + 23. But how do I show my work?

1 answer:

Digiron [165]3 years ago

8 0

Answer:

Step-by-step explanation:

5+6 (2x + 3) -2x = 10x + 23

5 + 6(2x-3) -2x = 10x+23

10x + 23 = 10x + 23

-23 -23

10x = 10x

-10x -10x

0 = 0

Or if you divide will be

10x = 10x / ÷10

X= 1

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2abc-3ab if a=2, b=-3, c=2

Elden [556K]

So a=2 since a is next to the first 2 it would be 2x2 which equals 4 next it’s B and B= -3 so -3x4 equals -12 and then c also equals 2 so it would be -12x2 and that equals -24. Moving on to the next part as I said a=2 so it would be 3x2 and that equals 6 next it’s B again so 6x -3 equals -18 so now take -24 and -18 and subtract them and you would get -6. Sorry if this answer is wrong I did my best...hope it helped.

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3 years ago

3.5 - 1.05 please help

netineya [11]

Answer:

The answer is 2.45

Step-by-step explanation:

I used this magic device called a calculator!

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3 years ago

Read 2 more answers

I need this answer rn it’s important plz help me

timurjin [86]

Answer:

y- intercept = 22

Step-by-step explanation:

to find the y- intercept substitute x = 0 into f(x)

f(0) = (0 - 11)(0 - 2) = - 11 × - 2 = 22 → (0, 22 )

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3 years ago

Find the equation of the tangent line to the curve <br> 2exy=x+y at (0,2).

DiKsa [7]

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function = f(x,y) = $2e^{xy} -x-y=0$ ...(i)

Differentiating equation (i) with respective to 'x' , we get

$2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0$

apply formula

$\frac{d}{dx} (UV) = UV^{l} +V U^{l}$

<u><em>step(ii):-</em></u>

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0$

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0$

Taking common d y/d x

$(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))$

$\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}$

put At (0,2)

$\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3$

slope of the curve m = 3

<u><em>Step(iii)</em></u>:-

The equation of the tangent line to the curve

$y-y_{1} =m(x-x_{1} )$

y - 2 = 3 ( x - 0 )

3 x - y = 2

<u><em>Final answer:-</em></u>

The equation of the tangent line to the curve

3 x - y = 2

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3 years ago

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Lelu [443]

Answer:

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Step-by-step explanation:

If you wanted to solve the inequality then the answer would be x<12

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3 years ago