All categories

3 years ago

SOS I NEED ANSWER RIGHT NOW SOMEONE PLEASE HELP ME :(

Mathematics

1 answer:

laila [671]3 years ago

3 0

Answer:

The functions share a y intercept of -1

Step-by-step explanation:

Both functions cross the y axis and y=-1 and x=0

They both have the same y intercept

You might be interested in

If f(x) = x2 + 1 and g(x) = x -4, which value is equivalent to (f•g)(10)?

Phantasy [73]

Answer:

Step-by-step explanation:

(f•g)(x) = (x - 4)² + 1

then

(f•g)(10) = (10 - 4)² + 1 = 6² + 1 = 37

4 0

3 years ago

The circle graph below shows the Johnson family budget for one month.

IceJOKER [234]

Answer
1/3

hope this helps have a nice day:)

4 0

3 years ago

Read 2 more answers

Find the area of the circle (radius = 6)

Rainbow [258]

Step-by-step explanation:

Area of the circle = pi×r²

= 22/7 × 6 × 6

= 113.14 unit²

4 0

3 years ago

Read 2 more answers

Find The Five<br> Rational number<br> Between<br>-3/2 and 5/3

Umnica [9.8K]

here is your answer

1.61 , 1.6245, 1.512, 1.432, 1.32456

Step-by-step explanation:

covert fraction to decimal we get,

-3/2 = -1.5 and 5/3 = 1.70

and any number that lies between these two numbers which is terminating and non repeating or non terminating repeating.. that are the numbers that you need.

3 0

3 years ago

An NFL coach sometimes uses a defense that utilizes 3 defensive linemen, 4 linebackers, and 4 defensive backs. His roster (the p

Alexandra [31]

Answer:

68,600

Step-by-step explanation:

The order of the players is not important. For example, a defensive line of Shaq Lawson, Ed Oliver and Jerry Hughes is the same as a defensive line of Ed Oliver, Shaq Lawson and Jerry Hughes. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Defensive Lineman:

3 from a set of 8. So

$C_{8,3} = \frac{8!}{3!5!} = 56$

56 combinations of defensive lineman

Linebackers:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of linebackers

Defensive backs:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of defensive backs

How many different ways can the coach pick the 11 players to implement this particular defense?

56*35*35 = 68,600

68,600 different ways can the coach pick the 11 players to implement this particular defense

7 0

3 years ago