Answer:
The additive inverse of 0 is 0.
Answer:
41 and 77
Step-by-step explanation:
x: his age the first time he went to space
y: his age the second time he went to space
the second time he went to space he was 5 years younger than twice the age when he went his first time, then:
y = 2x - 5
the sum of both ages is 118, then:
x + y = 118
If you replace y = 2x - 5 in x + y =118:
x + 2x - 5 = 118
3x = 123
x = 41
replacing x:
41 + y = 118
y = 118 - 41
y = 77
so when he was 77, he was 5 years younger than twice 41 ( 41*2 = 82 => 82 - 5 =77)
One possible solution is
f(x) = x^4
g(x) = x-3
Since
f(x) = x^4
f(g(x)) = ( g(x) )^4
f(g(x)) = ( x-3 )^4
=================================================
Another possible solution could be
f(x) = x^2
g(x) = (x-3)^2
Because
f(x) = x^2
f(g(x)) = ( g(x) )^2
f(g(x)) = ( (x-3)^2 )^2
f(g(x)) = (x-3)^(2*2)
f(g(x)) = (x-3)^4
Answer:
1.12x14=208
Step-by-step explanation:
base X height
Answer:
what is the question lol
Step-by-step explanation:
