Answer for #12 Is Length = 630FT & Width 335 FT
Answer for #13 is 4600 Items & 7800 Items. I have this workbook with the same problems :) Hope this helped :)

6 0

3 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

8 0

3 years ago

Can someone please give me the answers to this? ... please ...

Gelneren [198K]

Step-by-step explanation:

the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).

so,

(9, 7) to (4, -3)

midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)

(-7, -5) to (2, 1)

midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)

now we have the midpoint and need the second point.

(4, 2) over (3, 4) to (x, y)

3 = (4 + x)/2

6 = 4 + x

x = 2

4 = (2 + y)/2

8 = 2 + y

y = 6

(-2, 1) over (-3, 2) to (x, y)

-3 = (-2 + x)/2

-6 = -2 + x

x = -4

2 = (1 + y)/2

4 = 1 + y

y = 3

5 0

2 years ago

7/2 + x/2 = -5x + 5/3 <br><br> solve for x

Novosadov [1.4K]

Answer:

give a heart and 5 stars

Step-by-step explanation:

7 0

2 years ago