<span>∫[(secx)−1<span>]<span>(1/2)</span></span>dx?</span> or <span>∫[sec(x−1)<span>]<span>(1/2)</span></span>dx hope it works</span>
For this case we first calculate the rate in blocks per minutes.
rate = (15.5) / (35) = 0.443 blocks per minutes.
Then, we can go to blocks per hour.
Remember: 1h = 60min.
rate = 0.443 * (1/60) = 0.00738 blocks per hour.
answer
his rate in blocks per hour is 0.00738 blocks per hour.
Answer:
ft
Step-by-step explanation:
A Cheetah can run at 103 ft/s.
A Zebra can run at x ft/s.
We have to use distributive property, in the distributive property we multiply a sum by multiplying each addend separately and then add the products.

In ten seconds, Cheetah will cover,

In ten seconds, Zebra will cover,

So the distance by which Cheetah is farther than Zebra is,

=
(Use of distributive property)
Answer:
80 and 90, it is 81.
Step-by-step explanation:
it's 51 but i would give brainlyst to the other person so yeah hope this help you :)