The recursive formula of the geometric sequence is given by option D; an = (1) × (5)^(n - 1) for n ≥ 1
<h3>How to determine recursive formula of a geometric sequence?</h3>
Given: 1, 5, 25, 125, 625, ...
= 5
an = a × r^(n - 1)
= 1 × 5^(n - 1)
an = (1) × (5)^(n - 1) for n ≥ 1
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Answer:
Five more than the square of a number= 5 + x²
Five more than twice a number = 5 + 2x
Five less than the product of 3 and a number = 3x - 5
Five less the product of 3 and a number = 5 -3x
Twice the sum of a number and 5 = 2(x + 5)
The sum of twice a number and 5 = 2x + 5
The product of a cube of a number and 5= 5x³
The cube of the product of 5 and a number= (5x)³
Answer:
ok is this supposed to be a quesion to ask or a fact?
Step-by-step explanation:
Answer:
I know another one
Step-by-step explanation:
THERES HYDROIGEN AND HELIUM THEN LITHNIUM BERILIUM BPRON CARBON EVERYWHERE NITROGEN ALL THROUGH THE AIR WITH OXYGEN SO U CAN BREATHE AND FLUORINE FOR UR PRETTY TEETH
Logx (8x-3) - logx 4 = 2
logx [(8x-3)/4] = 2
x^2=(8x-3)/4
4x^2=4(8x-3)/4
4x^2=8x-3
4x^2-8x+3=8x-3-8x+3
4x^2-8x+3=0
4(4x^2-8x+3=0)
(4^2)(x^2)-8(4x)+12=0
(4x)^2-8(4x)+12=0
(4x-2)(4x-6)=0
2(4x/2-2/2)2(4x/2-6/2)=0
4(2x-1)(2x-3)=0
4(2x-1)(2x-3)/4=0/4
(2x-1)(2x-3)=0
Two options:
1) 2x-1=0
2x-1+1=0+1
2x=1
2x/2=1/2
x=1/2
2) 2x-3=0
2x-3+3=0+3
2x=3
2x/2=3/2
x=3/2
Answer: Two solutions: x=1/2 and x=3/2
