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melisa1 [442]
3 years ago
13

The circle graph above shows the distribution of utility expenses for the Hierra family last year. If the family’s total utility

expenses last year were $3,600, what were their expensive go water and sewer.
Water and sewer=X%
Electric=30%
Heating and gas=50%
Mathematics
1 answer:
postnew [5]3 years ago
4 0

Answer:

The correct answer is - $720 or 20%.

Step-by-step explanation:

Given:

Total expense = 3600

Electric=30%

Heating and gas=50%

Water and sewer=X%

Solution:

For electric: 3600*30/100 = 1080

for heating and gas: 3600*50/100 = 1800

Left money for expense of water and shower = total - (electric and heating)

= 3600-1880

= 720

Percentage of water and shower = 720*100/3600

= 20%

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What is the value of x?
Sedaia [141]

Answer:

  x = 7 cm

Step-by-step explanation:

The two triangles are similar so ...

  x/(6 cm) = (42 cm)/(36 cm)

Multiplying by 6 cm, you get ...

  x = (6 cm)(42 cm)/(36 cm) = (6 cm)(7/6)

  x = 7 cm

3 0
4 years ago
Select the correct answer from each drop-down menu
Yakvenalex [24]

Answer:

First row. = -393 74 287

Second row = 471. 162 91

Third row =251 222 - 349

Step-by-step explanation:

For the first row

Cofactor of 12= (-8*15)-(21*13)

= -120-273

= -393

Cofactor of 23 = (11*15)-(7*13)

= 165-91

= 74

Cofactor of -6 = (11*21)-(-7*8)

= 231+56

= 287

For the second row

Cofactor of 11 = (23*15)-(21*-6)

= 345+126

= 471

Cofactor of -8 = (12*15)-(7*-6)

= 120 + 42

= 162

Cofactor of 13 (12*21)-(23*7)

= 252-161

= 91

For third row

Cofactor of 7= (23*13)-(-8*-6)

= 299-48

= 251

Cofactor of 21 = (12*13)-(11*-6)

= 156+66

=222

Cofactor of 15 = (12*-8)-(11*23)

= -96 - 253

=- 349

8 0
3 years ago
A polynomial equation with rational coefficients has the roots:​
Sedbober [7]

Answer: (5 - √1) and (4 + √7)

Step-by-step explanation:

Here we have 4 roots, then this is a polynomial of 4th degree.

We can write it as

a*x⁴ + b*x³ + c*x² + d*x + e = 0

We could rewrite this as the product of two quadratic equations:

(a₁*x² + b₁*x + c₁)*(a₂*x² + b₂*x + c₂) = 0

This will be equal to zero when (a₁*x² + b₁*x + c₁) is equal to zero, and when

(a₂*x² + b₂*x + c₂) is equal to zero.

Then we need to find the roots of these two quadratic equations.

And we know that the roots of a quadratic equation like:

a₁*x² + b₁*x + c₁ are given by:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a} = \frac{-b}{2a}   +-\frac{\sqrt{b^2 - 4ac}}{2a}

Then the general form of the roots is something like:

A +-\sqrt{B}

This means that if one of the roots is:

5 + √1, we must have another root equal to 5 - √1

And if we have one root equal to 4 - √7, then we must have another root equal to 4 + √7

Then the correct options are:

(5 - √1) and (4 + √7)

5 0
3 years ago
Which statement about this equation is true?
Viktor [21]
The equation has no solution because:

5(n+10)=5n+10n
5n+10n=5n+10n
I subtract 5n from both sides
10n=10n
Only one side is supposed to have the variable which is n, so the equation has no solution.
4 0
3 years ago
Please help what is the area and the perimeter of these two shapes????
34kurt

Answer:

Pink:

A. 87 m²

P. 50 m

Yellow:

A. 132 m²

P. 76 m

Step-by-step explanation:

You can cut the shapes up to find the area.

Pink Figure: (not cut up)

A.

(13×7)-(4×1)=

91-4=

87 m²

P.

(1+1+4+4)+(7+13+7+13)=

10+40=

50 m

Yellow Figure:

A.

(14×4.5)+((14-9-3)×3)+((12-4.5-3)×14)=

(14×4.5)+(2×3)+(4.5×14)=

63+6+63=

132 m²

P.

14+4.5+3+3+3+4.5+14+4.5+9+3+9+4.5=

76 m

4 0
3 years ago
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