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3 years ago

PLEASE HELP ASAP!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics

1 answer:

Pepsi [2]3 years ago

6 0

Answer: 8.69 (read explanation)

Step-by-step explanation:

If the one above it is only 8 and x is slightly better it would make much more sense for it to be 8.69..... try it, it sounds quit accurate.

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Kamila [148]

Answer:

It a choose so the answer is D

3 0

3 years ago

Which is an x-intercept of the continuous function in the

Paladinen [302]

Answer:

(-1, 0), (2, 0), (3, 0)

Step-by-step explanation:

x-intercept of a line is defined by a point where y = 0.

So the point in the form of (x, 0) will be the x-intercept of the given continuous function.

From the table attached,

For x = -1, f(-1) = 0

For x = 2, f(2) = 0

For x = 3, f(3) = 0

Points (-1, 0), (2, 0) and (3, 0) are the x-intercepts of the continuous function f(x).

5 0

3 years ago

Use your line plot and answer the question below

Wittaler [7]

Answer:

hgvcffgebebddbb

Step-by-step explanation:

hhgffggggvgfgfgcccc

5 0

2 years ago

The base of the following pyramid is a square. If the surface area of the pyramid is 896 in^2, what is it's volume? Side base le

MatroZZZ [7]

Answer: 457.3

Step-by-step explanation:

$V=\frac{lwh}{3}$

$V=\frac{14*14*7}{3}$ = 457.3

7 0

3 years ago

It is desired to draw blood 3 cm up a capillary tube. Assuming a contact angle of 0 degrees and a blood density of 1060 kg/m3, w

JulijaS [17]

Answer:

If we assume a temperature of 20ºc and the blood interfacial surface tension is similar to water interfacial surface tension, the diameter of the capillary tube should be 0.933mm.

Step-by-step explanation:

The Jurin law describes the height a fluid can reach in a capillary tube. This law can be written as:

$H=\displaystyle\frac{2\gamma cos(\theta)}{\rho gr}$

where γ is the interfacial surface tension, θ is the contact angle with the fluid, ρ is the fluid density, g is the gravity acceleration and r is the tube radius.

If we assume that the interfacial surface tension of blood and water are almost the same, γ=0,0728 N/m at 20ºc. Therefore the diameter of the tube will be:

$D=2r=\displaystyle\frac{4\gamma cos(\theta)}{\rho gH}=0.933\cdot 10^{-3}m$

4 0

3 years ago