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Softa [21]
2 years ago
12

PLEASE HELP WITH THIS ONE QUESTION

Mathematics
1 answer:
Snezhnost [94]2 years ago
8 0

Answer:

The fourth option.

Step-by-step explanation:

In the given equation x^2 + 4x + 9 = 0, a=1, b=4, and c=9. The quadratic formula is in the attachment below so if you plug in a, b, and c you get the fourth option.

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Solve: 12 dogs decreased by 25% step by step pls.
Annette [7]
Decreased by 25%
find 25% of 12 and decrease 12 by it

percent means parts out of 100
25%=25/100=1/4
'of' means multiply
25% of 12=1/4 times 12=3

decrease 12 by 3
12-3=9

answer is 9
8 0
3 years ago
Read 2 more answers
You are knitting a blanket. You want the area of the blanket to be 24 feet squared . You want the length of the blanket to be 2
Sauron [17]
Think of it this way: x multiplied by a number that is two more than x is y.
So, look at the factors. 3 and 8 wouldn't work, because 8 is 5 longer than 3. 1 and 24 wouldn't work, because 24 is 23 more than 1. 12 and 2 is also not going to work; 12 is 10 more than 2. What you have left is 4 and 6. 6 is 2 more than 4, and they both multiply to get 24.

So, the correct answer is 6 feet long and 4 feet wide.
4 0
3 years ago
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Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Alisiya [41]

Answer:

The answer is C: X = 3

Step-by-step explanation:


5 0
3 years ago
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Which expression is equivalent to
pychu [463]

Answer:

Step-by-step explanation:

i cannot find an answer from the expression but i can guess if you didnt follow pemdas, it would be d

3.5 × 102  is 357

(8 × 10−4) + (6 × 10−4)  is 132

132/357= .369 or .37 or 0 simplified

d is 4*10-10

10-10 is 0

4*0 is 0

8 0
3 years ago
It is given that p varies inversely as q. If p = 12 and q = 45 find p, if q is 135.
alexgriva [62]

Answer:

p =4

Step-by-step explanation:

Given

Variation: Inversely

p = 12 when q = 45

Required

Determine p when q = 135

First, we need to determine the relationship between p and q

Since, it is an inverse variation.

The relationship is:

p\ \alpha\ \frac{1}{q}

Convert to an equation

p= k *\frac{1}{q}

p= \frac{k}{q}

Where k = constant of variation

Make k the subject

k = p * q

When p = 12 and q = 45

k = 12 * 45

k = 540

To solve for p when q = 135

Substitute 135 for q and 540 for k in p= \frac{k}{q}

p = \frac{540}{135}

p =4

6 0
2 years ago
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