Answer: 432 units²
Step-by-step explanation:
The figure is composed by two trapezoids.
The formula for calculate the area of a trapezoid is:
Where "B" is the larger base, "b" is the smaller base and "h" is the height.
Let be 
the area of the figure, 
the area of the trapezoid on the left and 
the area of the trapezoid of the right. Then the area of the figure will be:
Substituting values, you get:
<h3> </h3>
Taking a quotient, we will see that she can make 7 bowls of cereal (and some leftover milk).
<h3>How many bowls of cereal would kathy have?</h3>
We know that for each bowl, she needs 1/2 cups of milk.
And we also know that she has a total of (3 + 3/5) cups of milk.
To know how many bowls she can make, we need to take the quotient between the total that she has and the amount that she needs for each bowl:
(3 + 3/5)/(1/2)
We can rewrite the total as:
3 + 3/5 = 15/5 + 3/5 = 18/5
Then the quotient becomes:
(18/5)/(1/2) = (18/5)*2 = 36/5 = 35/5 + 1/5 = 7 + 1/5
So she can make 7 bowls of cereal (and some leftover milk).
If you want to learn more about quotients:
brainly.com/question/629998
#SPJ1
Answer:
a) 72 cm^2
b) 9 cm^2
c) 9 cm^2
d) 60.39 cm^2
Step-by-step explanation:
a) the the length is 12 cm and the width is 6 cm. Area = lw
A=(12)(6)
A=72 cm^2
b) base equals 3 cm
Height equals 6 cm
A=1/2(3)(6)
A= 9 cm^2
c) base = 3 cm
height=6 cm
Area=1/2(3)(6)
A=9 cm^2
d) to to find the area of the parallelogram, You need to use Pythagorean theorem for one of the triangles.
3^2 + 6^2 = x^2
9 + 36 = x^2
45=x^2
✓45 = ✓x^2
x = 6.71 cm
12-3 = 9
now that you have all the sides for the parallelogram, multiply 6.71 times 9 to get the area.
A= 60.39 cm^2
Divide the number that islf can divide by like 2 or 3 or 4 for exaples
9514 1404 393
Answer:
x = 1 or 5
Step-by-step explanation:
The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...
Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.
_____
<em>Comment on "cross multiply"</em>
Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.
What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.
