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VMariaS [17]
3 years ago
6

Which of the following functions is graph below ​

Mathematics
1 answer:
svetlana [45]3 years ago
7 0

Answer:

d because i love and wanna help you

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41/17 rounded to the nearest hendreth
Andrews [41]

Answer:

2.47

Step-by-step explanation:

convert it to a decimal = 2.47058823....

then round that to a nearest hundredth = 2.47

3 0
3 years ago
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Solve for a.<br> 7a + 18 = 102<br> a =
Virty [35]

Answer:

12

Step-by-step explanation:

6 0
4 years ago
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24. A farmstand collected $350 from sales on Wednesday. This amount was $75
larisa [96]

Answer:

$100

Step-by-step explanation:

Given:

  • Wednesday sales = $350

If the amount collected from sales on Wednesday was <u>$75 greater</u> than the amount collected from sales on Tuesday, then Tuesday's sales were $75 <u>less</u> than Wednesday's sales:

  • Tuesday sales = $350 - $75 = $275

If the amount collected from sales on Wednesday was <u>two times as great</u> as the amount collected from sales on Monday, then Monday's sales were <u>half</u> Wednesday's sales:

  • Monday sales = $350 ÷ 2 = $175

To calculate how much more the farmstand collected from sales on Tuesday than it collected on Monday, <u>subtract</u> the Monday sales from the Tuesday sales:

  • $275 - $175 = $100
8 0
2 years ago
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hannahs hourly wage at the icecream shop is $5.85. the table shows the number of hours she worked. She estimates her earnings to
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109.69 is act ual so her estimate is more
5 0
3 years ago
Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6
horsena [70]

Answer:

x^{4} -18x^{3}+104x^{2} -172x-100

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:  

\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))(  x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\

7 0
3 years ago
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