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3 years ago

What is the midpoint of FB

Mathematics

1 answer:

VMariaS [17]3 years ago

3 0

Answer:

Point L as it is the midpoint of FB

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Sketch a graph of the polynomial function f(x) = –x3 + 5x2 – 2x – 8. Use the graph to complete the following:

Darya [45]

Answer:

decreasing

Step-by-step explanation:

If you put the function in desmos, everything up until -1 is decresaing still.

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2 years ago

Let R be the region bounded by the following curves. Let S be the solid generated when R is revolved about the given axis. Ifpo

steposvetlana [31]

The two curves $y=x$ and $y=x^{1/15}$ intersect at $x=0$ and $x=1$ , with $x^{1/15}\ge x$ over $0\le x\le1$ .

Washer method

$\displaystyle\pi\int_0^1\left(\left(x^{1/15}\right)^2-x^2\right)\,\mathrm dx=\pi\int_0^1\left(x^{2/15}-x^2\right)\,\mathrm dx=\pi\left(\frac{15}{17}-\frac13\right)=\boxed{\frac{28\pi}{51}}$

Shell method

We have $y=x^{1/15}\implies x=y^{15}$ . The curves $x=y$ and $x=y^{15}$ intersect at $y=0$ and $y=1$ , with $y\ge y^{15}$ over $0\le y\le1$ .

$\displaystyle2\pi\int_0^1y\left(y-y^{15}\right)\,\mathrm dy=2\pi\int_0^1\left(y^2-y^{16}\right)\,\mathrm dy=2\pi\left(\frac13-\frac1{17}\right)=\boxed{\frac{28\pi}{51}}$

6 0

3 years ago

Teru burned about 1,000 calories downhill skiing before lunch. If she plans to ski

Fudgin [204]

Answer:

3.3333 hours

Step-by-step explanation:

From the attached table :

Downhill skiing for 1/6 hours ; results in 100 calories burn

To burn 1000 calories :

Skiing hours required :

(1000 / 100) * (1/6)

10 * 1/6 = 10 /6 hours

Planned skiing hours = 5

Number of skiing hours after lunch will be :

5 hours - 10/6 hours

5 hours - 1.6666 hours

= 3.3333 hours

4 0

2 years ago

How do I divide 581 by 120 ?

s2008m [1.1K]

The answer is <span>4.84166667</span>

7 0

3 years ago

a leaf hangs from a branch 12 feet in the air. it falls to the ground at a rate of 0.25 feet per second. which graph could repre

Kipish [7]

For this case we have an equation of the form:
$h (t) = (1/2) * (a) * (t ^ 2) + v0 * t + h0
$
Where,
h0: initial height
v0: initial speed
a: acceleration
Substituting values we have:
$h (t) = (1/2) * (- 32) * (t ^ 2) + 0.25 * t + 12
$
Rewriting we have:
$h (t) = -16t ^ 2 + 0.25 * t + 12
$
Note: see attached image
Answer:
$h (t) = -16t ^ 2 + 0.25 * t + 12$

7 0

2 years ago