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Alenkasestr [34]
3 years ago
14

What is the length of the diagonal, ddd, of the rectangular prism shown below?

Mathematics
1 answer:
Papessa [141]3 years ago
4 0

Answer:

7

Step-by-step explanation:

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Consider this story problem: "Priscilla bought cheese that weighs ¾ pounds. If she divides it into portions that are each 1/8 po
Katena32 [7]

Answer:

4

Step-by-step explanation:

8 0
2 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Find the point-slope form of the equation of the line that passes through the given point and has the indicated slope. Point: (-
zzz [600]

Answer:

slope : 3

y + 3 = 3(x + 5)

y + 3 = 3x + 15

y = 3x + 12

5 0
3 years ago
Solve the system of equations using the addition method.
stepladder [879]

Answer:

A) 5x - 2y = 12

B) 3x + 2y = 36  Adding both equations eliminates "y"

8x = 48

x = 6   Putting x=6 into equation B we get

3*6 + 2y = 36

2y = 18

y = 9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
SHOW ALL STEPS PLEASE !
il63 [147K]
Check the picture below.

make sure your calculator is in Degree mode.

6 0
3 years ago
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