Question

Write an expression for the area of a triangle with a height of 2x^2 units and a base of 5x^2+4x units

Answer 1

Answer:

The area of the triangle is $5x^4 + 4x^3$ square units

Step-by-step explanation:

Given

Shape: Triangle

$Height = 2x^2$

$Base = 5x^2+4x$

Required

The area of the triangle

The area of a triangle is calculated as thus;

$Area = \frac{1}{2}(base)(height)$

By substituting $Height = 2x^2$ and $Base = 5x^2+4x$; This gives

$Area = \frac{1}{2}(5x^2 + 4x)(2x^2)$

$Area = \frac{(5x^2 + 4x)(2x^2)}{2}$

$Area = (5x^2 + 4x)(x^2)$

Open Bracket

$Area = 5x^2 * x^2 + 4x * x^2$

$Area = 5x^4 + 4x^3$

Hence, the area of the triangle is $5x^4 + 4x^3$ square units