Answer:
a. x=-17, y=27
b. x=0, y=-6
c. x=9, y=-1
d. undefined
e. x=4, y=-6
f. x=4, y=0
Step-by-step explanation:
a. 3x+y=24
y=3x+24
-x+3x+24=-10
2x=-34
x=-17
-(-17)-y=-10
17-y=-10
-y=-27
y=27
b. 3y=-18
y=-6
-6=-x-6
0=x
c. -2x+17=8-x
9=x
y=8-9
y=-1
d. x-7=x+7
x-14=x
-14=0
e. -4x+10+2x=2
-2=-8
x=4
y=-4(4)+10
y=-16+10
y=-6
f. x+2y=4
x=4-2y
-4(4-2y)-3y=16
-16+8y-3y=16
-16+5y=16
5y=0
y=0
x+2(0)=4
x=4
Answer:2x times 2
Step-by-step explanation:
A polynomial ppp has zeros when x=-2x=−2x, equals, minus, 2, x=\dfrac13x= 3 1 x, equals, start fraction, 1, divided by, 3, end
Veronika [31]
Answer:
Polynomial equation is, ![p=(x+2)(3x-1)(x-3)=3x^3-4x^2-17x+6](https://tex.z-dn.net/?f=p%3D%28x%2B2%29%283x-1%29%28x-3%29%3D3x%5E3-4x%5E2-17x%2B6)
Step-by-step explanation:
Given:
The zeros of the polynomial,
, are
.
Therefore,
![x= -2\\(x+2)=0](https://tex.z-dn.net/?f=x%3D%20-2%5C%5C%28x%2B2%29%3D0)
So,
is a factor of the polynomial.
![x=\frac{1}{3}\\3x=1\\3x-1=0](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B3%7D%5C%5C3x%3D1%5C%5C3x-1%3D0)
So,
is a factor of the polynomial.
![x=3\\x-3=0](https://tex.z-dn.net/?f=x%3D3%5C%5Cx-3%3D0)
So,
is also a factor of the polynomial.
Therefore, a polynomial can be expressed in terms of the product of its factors.
Thus, ![p=(x+2)(3x-1)(x-3)](https://tex.z-dn.net/?f=p%3D%28x%2B2%29%283x-1%29%28x-3%29)
Expanding
, we get
![(x+2)(3x-1)=3x^2-x+6x-2=3x^2+5x-2](https://tex.z-dn.net/?f=%28x%2B2%29%283x-1%29%3D3x%5E2-x%2B6x-2%3D3x%5E2%2B5x-2)
Now, expanding
, we get
![(3x^2+5x-2)(x-3)=3x^3-9x^2+5x^2-15x-2x+6=3x^3-4x^2-17x+2](https://tex.z-dn.net/?f=%283x%5E2%2B5x-2%29%28x-3%29%3D3x%5E3-9x%5E2%2B5x%5E2-15x-2x%2B6%3D3x%5E3-4x%5E2-17x%2B2)
Therefore, the polynomial could be ![p=(x+2)(3x-1)(x-3)=3x^3-4x^2-17x+6](https://tex.z-dn.net/?f=p%3D%28x%2B2%29%283x-1%29%28x-3%29%3D3x%5E3-4x%5E2-17x%2B6)