The amount of water that the girls on the

Mathematics

2 answers:

solmaris [256]3 years ago

4 0

Answer:

35 oz less than

Step-by-step explanation:

oksian1 [2.3K]3 years ago

3 0

Answer:

the median of water drank on the basketball team is about haft of the the median in the soccer team.

Step-by-step explanation:

As we know that the median is the middle value so we need to rewrite the two plots in numerical values.

Basket team:

16 24 24 24 32 32 32 40 40 40 48 48 48 48 56 56

=> the median is: 40

Soccer team:

64 64 72 72 72 72 72 72 80 80 80 80 88 88 88 96

=> the median is: 76

So the median of water drank on the basketball team is about haft of the the median in the soccer team.

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The answer to this word problem usinf discriminant

solniwko [45]

$\bf h=-9.8t^2+45t+1.2\implies 64.5=-9.8t^2+45t+1.2
\\\\\\
0=-9.8t^2+45t-63.3\\\\
-------------------------------$

$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic}
\\\\\\
0=\stackrel{\stackrel{a}{\downarrow }}{-9.8}t^2\stackrel{\stackrel{b}{\downarrow }}{+45}t\stackrel{\stackrel{c}{\downarrow }}{-63.3}
~~~~~~
\stackrel{discriminant}{b^2-4ac}=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}
\\\\\\
(45)^2-4(-9.8)(-63.3)\implies -456.36$

the discriminant is a negative value, thus no solution for such quadratic, meaning if we use h=64.5 like we did, there's no "t" seconds at which point the ball hits the batting cage.

8 0

3 years ago

Write in numeric form. Nine hundred thirty six and twelve hundredths

4vir4ik [10]

That would be... 936.12

3 0

2 years ago

Read 2 more answers

Please help ! This is 7th grade math and I’ve been stuck on this question for 30 minutes!

FinnZ [79.3K]

$\dfrac{1}{22}\:\dfrac{\text{in}}{\text{hr}}$

Step-by-step explanation:

The amount of time from 10pm to 7am is 9 hours. However, the time indicated is 7:10am. Since there are 60 minutes in an hour, 10 min is equal to 1/6 of an hour. Therefore, the total time that the water level of the pool decreased is $9\frac{1}{6}$ hours or $\frac{55}{6}$ hours. To find the rate at which the water level decreased, we divide the change in the water (in inches) by the time it took to reach that level. So we write