9 = c(c - 8)
9 = c² - 8c
c² - 8c - 9 = 0
c² + c - 9c - 9 = 0
c(c + 1) -9 (c + 1) = 0
(c+1)(c-9) = 0
c = -1 or 9
In short, Your Answers would be -1 and 9
Hope this helps!
Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Why are B and C the same answer options?
the answer is 6.4444444444
so id say it either B or C but as they are the same i have no clear way to answer the question
either way its 6.4
False -1 is not a solution.