1. Use the formula d=rt. FInd the rate when d=13 mi and t=3 h.

A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the

hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone = 2 m

The angle which the A $\hat O$ C = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone

The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°

∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0

3 years ago

1500 people to part in a walkathon. 450 of them were school children. The rest are adults. What percentage of the participants w

Bas_tet [7]

70% of the people were adults

First you subtract 1500-450 = 1050
Then you divide 1050/1500 = .7

5 0

3 years ago

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Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

the lengths of the sides of BRAD are:

$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

$\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}$

Each side of KELY is twice the length of the corresponding side on BRAD. This makes the ratio of the sides 2:1 and the figures are similar.

8 0

3 years ago

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Can someone plzz help me with these 2 questions. thanks!

Deffense [45]

9514 1404 393

Answer:

4. height: 5√3 cm; area: 25√3 cm²

5. 30√2 ft ≈ 42.43 ft

Step-by-step explanation:

4. The height of an equilateral triangle is (√3)/2 times the side length, so is ...

height = (√3)/2 × (10 cm) = 5√3 cm

The area is given by the formula ...

A = 1/2bh

A = 1/2(10 cm)(5√3 cm) = 25√3 cm²

__

5. The diagonal of a square is √2 times the side length, so the distance from 3rd to 1st base is ...

(30 ft)√2 ≈ 42.43 ft

__

The length of the diagonal of a square is something you should be familiar with. If you're not, you can figure the distance using the Pythagorean theorem.

d = √(30² +30²) = √1800 ≈ 42.43 . . . feet

6 0

2 years ago

This is a bonus question

Elena L [17]

Answer:

10,500

Step-by-step explanation:

See this as 2 rectangles: a box of water (28cm), and another box with the height you want (35cm)

Area of Rectangle = lwh

For the water;

50 x 30 x 28= 42000

As for the needed volume:

50 x 30 x 35 = 52500

To find how much more water, subtract the smaller volume from bigger volume.

10500 should be the final answer

3 0

2 years ago

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