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Brut [27]
3 years ago
12

Timothy has a fenced-in garden in the shape of a rhombus. The length of the longer diagonal is 24 feet, and the length of the sh

orter diagonal is 18 feet.What is the length of one side of the fenced-in garden?
Mathematics
1 answer:
Stels [109]3 years ago
6 0
When you are looking at a rhombus you know that it will be 4 congruent triangles when the diagonals are added in. So if you draw the rhombus each of the triangles will have one side that is 12 feet and another that is 9. You can now use Pythagorean’s theorem to find the length of a side. The length will be 15 feet.
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Gelneren [198K]
The slide costs $2 each time you ride. $15/2 = 7.5 so you can ride it 7 times.
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3 years ago
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I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
WINSTONCH [101]

c = 39

hope it helps...!!!

6 0
2 years ago
Csc\theta -cot\theta =\frac{sin}{1+cos\theta }
Inga [223]

Answer:

Step-by-step explanation:

Left Hand Side

Change to sin(theta) and cos(theta)

csc(theta) = 1/sin(theta)

cot(theta) = cos(theta)/sin(theta)

1/sin(theta) - cos(theta)/sin(theta)                   Put over Sin(theta) Common denominator

[1 - cos(theta)] / sin(theta)                                Multiply numerator and denominator by 1 + cos(theta)

(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))

(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)

sin^2(theta) / (sin(theta)* ( 1 + cos(theta)

sin(theta) / (1 + cos(theta) )

Right hand Side.

See Above.

4 0
3 years ago
Joely's Tea Shop, a store that specializes in tea blends, has available 45 pounds of A grade tea and 70 pounds of B grade tea. T
prisoha [69]

Answer:

Hence, (75,40) is the maximum point and maximum profit is $192.5

Step-by-step explanation:

Let the breakfast be x

And  let the lunch or afternoon be y

Inequalities will become

\frac{1}{3}x+\frac{1}{2}y\leq 45

\frac{2}{3}x+\frac{1}{2}y\leq 70

And objective function will be

Z=1.5x+2.0y  

You can see the graph in the attachement

ABCD is the feasible region

Points of feasible region is (0,90) ,(0,0) ,(75,40) and(105,0)

We have to find Z by substituting the points of feasible region

At (0,90) we get

Z=1.5(0)+2(90)

Z=180

At (0,0)

Z=1.5(0)+2(0)

Z=0

At (75,40)

Z=1.5(75)+2(40)

Z=192.5

At (105,0)

Z=1.5(105)+2(0)

Z=157.5

The maximum number we are getting is 192.5 which is at (75,40)

Hence, (75,40) is the point of maximum

4 0
3 years ago
Ivan found the change in a scale factor. His work is shown below. What error did Ivan make?
storchak [24]

Answer:

45

Step-by-step explanation:

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3 years ago
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