Volume of a cylinder = πr^2 h = π x (2)^2 x 3 = π x 4 x 3 = 12π = 37.7 cm^3
Answer:
12 meters
Step-by-step explanation:
Looking at the problem we can see that it typifies a right angled triangle. The rope running from the top of the flagpole to the hook on the ground is the hypotenuse of the triangle. Let us call this hypotenuse c. Let the distance between the hook and the foot of the flagpole be b. Let the height of the flagpole be a.
From Pythagoras theorem;
c^2 = a^2 + b^2
a^2= c^2 - b^2
a= √c^2-b^2
From the question
c= 13 metres
b= 5 metres
a= the unknown
a= √c^2-b^2
a= √(13)^2 - (5)^2
a= √169 - 25
a= √144
a= 12 meters
Answer:
39 sq cm
Step-by-step explanation:
Ok. Since ΔAED is isosceles, then the height of the trapezoid is 3 cm
One base is 16 and the other base is 16 - 3 - 3 = 10.
A = 1/2 h(
+ 
) where and are lengths of the bases
A = 1/2(3)(10 + 16)
= 1/2(3)(26)
= 39 sq cm
Answer:
the anser is 4 im pretty sure.
Step-by-step explanation: 3*6 is 18 and 4*4 is 16. 18 minus 16 is 2 multiplied by the other 2 is 4.
According to Vertical Line test, a vertical line only intersect the graph of a function at one point. Among the choices given, x = 4 is a vertical line. So this line cannot intersect the graph of a function at more than one point. The other three would apply. So the answer choices are A, C and D.
