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Savatey [412]
3 years ago
5

The dimensions of a rectangle are increased by a scale factor of 2. If the original rectangle had an area of 16 square feet, wha

t is the area of the larger rectangle?

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

64 ft squared.

Step-by-step explanation:

I have attached the work to your problem.

Please see the attachment below.

I hope this helps!

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The Cavalier can drive for 86.4 km on 6 litres of gas. What is the fuel
ale4655 [162]

Answer:

number of kilometers travelled by cavalier-86.4

he used 6litres for the journey. take number of kilometers divide by number of litres

86.4/6=14.4

5 0
2 years ago
6x²+11x-2 help me fast​
Mekhanik [1.2K]

Answer:

(6x-1)(x+2)

Step-by-step explanation:

6x^2 = (6x  (x

(6x -1)(x+2)

6x * x = 6x^2

6x * 2 = 12x - 1x = 11x

-1*2 = -2

6x^2 + 11x - 2

8 0
3 years ago
An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
4 years ago
Can yall help me pls?
adell [148]
327 is the answer I think
6 0
3 years ago
Read 2 more answers
How to solve (4+5)÷3×4
Evgesh-ka [11]
We Need To Remember Order of Operations.

So, We Do:
4+5.
We Know That 4 + 5 = 9, So We Have:
9 <span>÷ 3 * 4
Now, We Do:
9 </span><span>÷ 3 
This Is 3, So We Have:
3 * 4. 
We Know That 3 * 4 Is 12, So:

We Know That The Answer To This Expression Is 12.</span>
3 0
4 years ago
Read 2 more answers
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