All categories

3 years ago

B. If p +q= 3 and pq - 4. find the value of p³+q³

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer:

p + q = 3 = = 3

p q − 4 = = 3

p 3 + q 3 = = 3

Step-by-step explanation:

Use the given functions to set up and simplify p 3 + q 3 .

STatiana [176]3 years ago

7 0

Answer:

p³ + q³ is -9

Step-by-step explanation:

${ \tt{ {(p + q)}^{3} = ( {p}^{2} + {q}^{2} + 2pq)(p + q) }} \\ { \tt{ {(p + q)}^{3} = ( {p}^{3} } + 3p {q}^{2} + 3 {p}^{2} q)} \\ { \tt{ {p}^{3} + {q}^{3} = {(p + q)}^{3} - 3pq(p + q)}} \\ { \tt{ {p}^{3} + {q}^{3} = {(3)}^{3} - 3(4)(3) }} \\ = - 9$

You might be interested in

What are the relative frequencies, to the nearest hundredth, of the rows of the two way table?

Nookie1986 [14]

Answer: A B

Group A 0.25 0.75

Group B 0.45 0.55

Step-by-step explanation:

Since we have given that

Number of people of A in Group A = 15

Number of people of B in Group A = 45

Number of people of A in Group B = 20

Number of people of B in Group B = 25

Total number of people in Group A = 15+45 = 60

Total number of people in Group B = 20+25 = 45

So, Relative frequencies will be given below:

Relative frequency of A in Group A is given by

$\frac{15}{60}=0.25$

Relative frequency of B in Group A is given by

$\frac{45}{60}=0.75$

Relative frequency of A in Group B is given by

$\frac{20}{45}=0.45$

Relative frequency of B in Group B is given by

$\frac{25}{45}=0.55$

Hence, A B

Group A 0.25 0.75

Group B 0.45 0.55

5 0

3 years ago

Please help me answer thanks.

Dmitry_Shevchenko [17]

Answer:

see explanation

Step-by-step explanation:

Given that M is directly proportional to r³ then the equation relating them is

M = kr³ ← k is the constant of proportion

To find k use the condition when r = 4, M = 160, thus

160 = k × 4³ = 64k ( divide both sides by 64 )

2.5 = k

M = 2.5r³ ← equation of variation

(a)

When r = 2, then

M = 2.5 × 2³ = 2.5 × 8 = 20

(b)

When M = 540, then

540 = 2.5r³ ( divide both sides by 2.5 )_

216 = r³ ( take the cube root of both sides )

r = $\sqrt[3]{216}$ = 6

5 0

4 years ago

A sample of n = 10 automobiles was selected, and each was subjected to a 5-mph crash test. Denoting a car with no visible damage

solmaris [256]

Answer:

a) From definition the proportion of successes would be:

$\hat p = \frac{x}{n} = \frac{7}{7+3}= 0.7$

b) Data : 1,1,0,0,1,1,1,0,1,1

x = 7 for this case

$\hat p = \frac{7}{10}=0.7$

The proportion in part (a) is exactly equal to the mean in part (b)

c) We have actually 7 successes and 3 fails and we want this condition:

$\frac{x}{n}=0.6$

The new value of n would be 25 so then we can solve for x and we got:

$x = 25*0.6= 15$

So we need 15 successes and we have 7 so then we need $15-7 = 8$ successes in the new 15 cars in order to satisfy the condition.

Step-by-step explanation:

Data: S S F F S S S F S S

S means success and F damage. We have 7 successes and 3 damages for this case

(a) What is the value of the sample proportion of successes x/n?(

From definition the proportion of successes would be:

$\hat p = \frac{x}{n} = \frac{7}{7+3}= 0.7$

(b) Replace each S with a 1 and each F with a 0. Then calculate x for this numerically coded sample.How does x compare with x/n?

Data : 1,1,0,0,1,1,1,0,1,1

x = 7 for this case

$\hat p = \frac{7}{10}=0.7$

The proportion in part (a) is exactly equal to the mean in part (b)

(c) Suppose it is decided to include 15 more cars in the experiment. How many of these would have to be S's to give x/n = 0.6 for the entire sample of 25 cars?

We have actually 7 successes and 3 fails and we want this condition:

$\frac{x}{n}=0.6$

The new value of n would be 25 so then we can solve for x and we got:

$x = 25*0.6= 15$

So we need 15 successes and we have 7 so then we need $15-7 = 8$ successes in the new 15 cars in order to satisfy the condition.

7 0

4 years ago

5491 apples were harvested from one side of the McMillan farm. they harvested 512 from the other side of the farm.about how many

Andrews [41]

Answer:

6003

Step-by-step explanation:

Given : They harvested 5491 apples from one side of the McMillan farm.

They harvested 512 from the other side of the farm.

To Find : The total number of apples harvested at the McMillan.

Solution :

Since we know that

Number of apples harvested from one side of the McMillan farm = 5491

Number of apples harvested from other side of the McMillan farm = 512

Now we are supposed to calculate the total number of apples

So, we need to sum the number of apples of both the sides .

⇒5491+512

⇒6003

Hence , the number of apples harvested at the McMillan is 6003

3 0

3 years ago

I need helpppppppppppppppppppppppplz

aleksandrvk [35]

Answer:

I need helpppppppppppppppppppppppplz

8 0

3 years ago

Read 2 more answers

B. If p +q= 3 and pq - 4. find the value of p³+q³​

B. If p +q= 3 and pq - 4. find the value of p³+q³