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Luda [366]
3 years ago
9

Choose the correct coefficients for the following reaction:

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
4 0

Hey there!

Mg(OH)₂ + H₂(SO₄) → Mg(SO₄) + H₂O

Balance O. (not including SO₄)

2 on the left, 1 on the right. Add a coefficient of 2 in front of H₂O.

Mg(OH)₂ + H₂(SO₄) → Mg(SO₄) + 2H₂O

Balance H.

4 on the left, 4 on the right. Already balanced.

Balance SO₄. (polyatomic ion)

1 on the left, 1 on the right. Already balanced.

Balance Mg.

1 on the left, 1 on the right. Already balanced.  

Our final balanced equation:

Mg(OH)₂ + H₂(SO₄) → Mg(SO₄) + 2H₂O

So your answer is a. 1, 1, 1, 2.

Hope this helps!

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The product of 2 × 104 cm and 4 × 10–12 cm, expressed in scientific notation is ____.
Hatshy [7]

Answer:

b,,

Explanation:

7 0
3 years ago
If you have 30.O g of hydrogen gas burned in excess oxygen how many moles of water can you make
vladimir1956 [14]

Answer:

15 moles

Explanation:

Data given:

mass of hydrogen (H₂) = 30.0 g

amount of oxygen (O₂) = excess

moles of water = ?

Solution:

First we look to the reaction in which hydrogen react with oxygen and make (H₂O)

Reaction:

              2H₂  + O₂  -----------> 2H₂O

Now look at the reaction for mole ratio

             2H₂  + O₂  -----------> 2H₂O

             2 mole                       2 mole

So it is 2:2 mole ratio of hydrogen to water

As we Know

molar mass of H₂  = 2(1) = 2 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now convert moles to gram

                  2H₂         +       O₂        ----------->    2H₂O

          2 mole (2 g/mol)                                 2 mole (18 g/mol)

                    4 g                                                     36 g

So,

we come to know that 4 g of hydrogen gives 36 g of water then how many grams of water will be produce by 30 grams of hydrogen.

Apply unity formula

                       4 g of H₂ ≅ 36 g of H₂O

                        30 g of H₂ ≅ X of H₂O

Do cross multiplication

                  X of H₂O =  30 g x 36 g / 4 g

                  X of H₂O =  270 g

Now convert grams of H₂O into moles

               No. of moles = mass in grams/molar mass

Put values in above formula

               No. of moles = 270 g / 18 (g/mol)

               No. of moles = 15 mol

so 30 gram of hydrogen produce 15 mol of water.

5 0
3 years ago
The Aurora Borealis or northern light occur when solar flares react with the atmosphere near the north poles. The Aurora give of
scoray [572]
Answer: <span>C) plasma
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4 0
3 years ago
Read 2 more answers
What is the net ion charge of Beryllium?​
KATRIN_1 [288]

Explanation:

Beryllium is a group 2 element and its atomic number is 4. Electronic configuration of beryllium is 1s^{2}2s^{2}.

Since, a beryllium contains two valence electrons so, in order to attain stability it will readily lose its 2 valence electrons.

Therefore, a beryllium atom upon losing two valence electrons will acquire a +2 charge.

Thus, we can conclude that the net ion charge of Beryllium is +2.

7 0
3 years ago
A 100.0 ml sample of 0.10 m ca(oh)2 is titrated with 0.10 m hbr. determine the ph of the solution after the addition of 400.0 ml
WINSTONCH [101]
The balanced equation for the reaction is as follows;
Ca(OH)₂ + 2HBr --> CaBr₂ + 2H₂O
stoichiometry of Ca(OH)₂ to HBr is 1:2
number of Ca(OH)₂ moles reacted - 0.10 mol/L x 0.1000 L = 0.010 mol
Number of HBr moles added - 0.10 mol/L x 0.4000 = 0.040 mol 
1 mol of Ca(OH)₂ needs 2 mol of HBr for neutralisation
therefore 0.010 mol of Ca(OH)₂  needs - 0.010 x 2 = 0.020 mol of HBr to be neutralised
but 0.040 mol of HBr has been added therefore number of moles of HBr in excess - 0.040 - 0.020 = 0.020 mol 
then pH of the medium can be calculated using the excess H⁺ ions
HBr is a strong acid therefore complete ionization
[HBr] = [H⁺]
[H⁺] = 0.020 mol / (100.0 + 400.0 mL)
      = 0.020 mol / 0.5 L 
      = 0.040 mol/L
pH = -log[H⁺] 
pH = - log [0.040 M]
pH = 1.40
pH of the medium is 1.40
8 0
3 years ago
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