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2 years ago

In the balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid, the products are:

Chemistry

1 answer:

earnstyle [38]2 years ago

7 0

The balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid is:

Sodium hydroxide + Sulfuric acid → Sodium sulfate +water

<h3>What is the balanced molecular equation?</h3>

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.

In the given reaction, the reactants have been sulfuric acid and sodium hydroxide. Thus, these are written on the left side of the right arrow. The sodium sulfate and water have been the products and written on the right side of the right arrow.

The balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid is:

Sodium hydroxide + Sulfuric acid → Sodium sulfate +water

Learn more about balanced molecular equations here:

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3 years ago

What mass of agno3 can be dissolved in 250g of water at 20°c?

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Hello there,

You should know the <span>solubility of AgNO3 in water at 20°C equals to 2220 g/L.

So we can say that in 1 L of water, 2220 g of AgNO3 can be dissolve.

Now you should know 1L = 1000g.

Which means 1000 g of water can dissolve 2220 g of AgNO3.

Therefore :

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So : </span> $x = \frac{250*2220}{1000} = \frac{555000}{1000}= 555g$ .

In short, 555g of AgNO3 can be dissolved in 250g of water at 20°C.

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