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photoshop1234 [79]
3 years ago
13

a triangle abc with vertices a (6,8) b(6,12) and c (10,12) is rotated 180 degrees. what are the coordinates of a

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0
It is (3,4), the coordinates is (3,4)
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Natalka [10]

2 because 8 divided by 4 is 2.

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2 years ago
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Which choices are equivalent to the expression below?<br> Check all that apply.
gavmur [86]
There’s no answer choices..
5 0
3 years ago
(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
Find the measure of the are or angle indicated. Assume that lines which appear tanget are tangents. ​
Brilliant_brown [7]

9514 1404 393

Answer:

  1. 85°
  2. 60°

Step-by-step explanation:

1. Angle JKL is half the measure of the intercepted arc JK.

  (1/2)JK = 1/2(360° -190°) = (1/2)(170°) = 85°

  angle JKL is 85°

__

2. The angle between tangents is the supplement of the intercepted arc.

  angle JKL = 180° -(360° -240°)

  angle JKL = 60°

8 0
3 years ago
The cone and the cylinder below have equal surface area. True or false.
WARRIOR [948]

Answer:

False

Step-by-step explanation:

The surface area of the cone is

V=\pi r^2 +\pi rl

SA=\pi r^2 +\pi\times r\times 2r

SA=\pi r^2 +2\pi\times r^2

SA=3\pi r^2

The surface area of the cylinder is:

SA=2\pi r^2 +2\pi rh

SA=2\pi r^2 +2\pi\times r\times r

SA=4\pi r^2

3 0
3 years ago
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