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Aleonysh [2.5K]
3 years ago
12

Use the triangle to evaluate each function. sin(A) = tan(A) = sec(A) =

Mathematics
2 answers:
nevsk [136]3 years ago
8 0

Part I

sin(A)= 3/5

tan(B)= 3/4

sec(A)= 5/4

Part II

B. cot(B)

Step-by-step explanation:

Nina [5.8K]3 years ago
5 0

Answer:

sin (A) = opposite / hypotenuse = BC / AB = 3/5

tan (A) = opposite / adjacent = BC / AC = 3/4

sec (A) = hypotenuse / adjacent = AB / AC = 5/4

Step-by-step explanation:

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Can you help me with this?<br> (I will give one of you brainliest)
Degger [83]

Answer:

1) \sqrt{9} and \sqrt{16} (between 3 and 4)

Explanation: \sqrt{9} and \sqrt{16} are the closest WHOLE squares root to \sqrt{12}; any other square roots wouldn't give us a whole number, or they're farther away from

2) -\sqrt{144} and -\sqrt{169} (between -(12) and -(13))

3) -\sqrt{36} and -\sqrt{49} (between -(6) and -(7))

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3 years ago
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Is (2,17) a one solution, no solution, infinite solution,or two solution
WARRIOR [948]

Answer:

one solution

Step-by-step explanation:

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3 0
3 years ago
15a^3+6a^2b-25ab^2-10b^3
bekas [8.4K]

Answer: 3a

​2

​​ (5a+2b)−5b

​2

​​ (5a+2b)

2 Factor out the common term 5a+2b5a+2b.

(5a+2b)(3{a}^{2}-5{b}^{2})(5a+2b)(3a

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Step-by-step explanation:

3 0
3 years ago
Could someone please help me asap!! Pleasseeeee and thanks.
kherson [118]

Answer:

Step-by-step explanation:

a² - b² = (a + b) (a - b)

1)x² - 36 = x² - 6² = (x + 6)(x-6)

2) 4x² - 16 = 4x² - 4*4 = 4(x² - 4)

                = 4(x² -2²)

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3) 9x² -1 = 3²x² - 1² = (3x)² - 1²

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8 0
4 years ago
9+3|5-x|=24<br><br> What is the lines for and how do I solve X with them?
Ivahew [28]

Answer:

the lines represent absolute value bars

x=0,10

Step-by-step explanation:

STEP 1: Move all terms not containing |5−x| to the right side of the equation.

3|5-x|=15

STEP 2: Divide each term by 3 and simplify.

|5-x|=5

STEP 3: Remove the absolute value term. This creates a ± on the right side of the equation because |x|=±x.

<em>5-x=±5</em>

STEP 4: Set up the positive portion of the ± solution.

5-x=5

STEP 5: Solve the first equation for x.

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NOTE: The solution to the equation includes both the positive and negative portions of the solution.

x=0,10

4 0
3 years ago
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