Answer:
10x + 3 = 6x + 5
Based on this, we have the lines y=10x+3 and y=6x+5. Both of the equations are linear, so they are straight lines when graphed. A system of straight lines can only have one solution maximum.
Solution:
x = 1/2
y = 8
(1/2 , 8)
Step-by-step explanation:
Start by expanding with the distributive property, then simplify by collecting like terms.
5(2x + 1) - 2 = 6x + 5 Multiply "5" with each term in the brackets.
10x + 5 - 2 = 6x + 5 Collect left side's like terms (5 - 2 = 3)
10x + 3 = 6x + 5
Based on this, we have the lines <u>y=10x+3 and y=6x+5</u>. A solution is the same as the POI (point of intersection). Both of the equations are linear, so they are straight lines when graphed. A system of straight lines can only have one solution maximum.
Some linear systems might have no solutions (when the lines are parallel) or infinite solutions (when the lines are equivalent, the same).
To find the solution, continue with the equation and isolate "x". This will give you the x-coordinate of the point of intersection.
To isolate 'x', move everything to the other side of 'x'. To move something, you do its reverse operation to both sides in reverse BEDMAS order.
10x + 3 = 6x + 5
10x - 6x + 3 = 6x - 6x + 5 Subtract 6x from both sides
4x + 3 = 5 "6x" cancelled out on the right. Simplified left (10x-6x=4x)
4x + 3 - 3 = 5 - 3 Subtract 3 on both sides. "3" on the left will cancel out
4x = 2 The right side was simplified (5 - 3 = 2).
4x/4 = 2/4 Divide both sides by 4 to isolate 'x'. Simplify right side.
x = 1/2 Solution's x-coordinate
Substitute what you found for 'x' into any equation that has 'y' (either <u>y=10x+3 or y=6x+5</u>). I will choose the first equation.
y = 10x + 3
y = 10(1/2) + 3 Multiply 1/2 and 10
y = 5 + 3 Add
y = 8 Solution's y-coordinate
Therefore the solution is when x=1/2 and y=8, or as an ordered pair, (1/2 , 8).
