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Pachacha [2.7K]
3 years ago
7

Let P(t) be the performance level of someone learning a skill as a function of the training time t. The derivative dP/dt represe

nts the rate at which performance improves. If M is the maximum level of performance of which the learner is capable, then a model for learning is given by the differential equation. dP/dt=k(M−P(t)), where k is a positive constant. Two new workers, David and Peter, were hired for an assembly line. David could process 11 units per minute after one hour and 14 units per minute after two hours. Peter could process 10 units per minute after one hour and 15 units per minute after two hours. Using the above model and assuming that P(0)=0, estimate the maximum number of units per minute that each worker is capable of processing.
Mathematics
1 answer:
irinina [24]3 years ago
5 0
So in your question where the P(t) is the value of the performance level of someone learning skill as a function of the training time T. The ask is to estimate the maximum number of units per minute to each worker is capable of processing and the answer is david 15.125
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4 years ago
N equals eight what is the value of 56 divided by n
PilotLPTM [1.2K]

Answer:7

Step-by-step explanation:

N=8

Divide:56/8=7

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Find parametric equation of a line with a slope of -2 and passes through (-10,-20)
rosijanka [135]
y- y_{0} =m(x- x_{0} ) \\ m= \frac{y_{1}- y_{0}}{x_{1}- x_{0} }  \\ y-(-20)= (-2)(x-(-10)) \\ y+20=-2x-20 \\ y=-2x-40
7 0
3 years ago
Part 1: What mistake did AJ make in the graph?
grigory [225]

Answer:

Part 1) AJ drawn the parabola opening upwards, instead of drawing it opening downwards

Part 2) see the explanation

Step-by-step explanation:

Part 1) What mistake did AJ make in the graph?

we have

f(x)=-(x+2)^2-1

This is the equation of a vertical parabola written in vertex form

The parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The vertex is the point (-2,-1)

therefore

AJ drawn the parabola opening upwards, instead of drawing it opening downwards

Part 2) Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake in the graph?

take the values x=-4 and x=4

For x=-4

substitute the value of x in the quadratic equation

f(x)=-(-4+2)^2-1\\f(x)=-5

For x=4

substitute the value of x in the quadratic equation

f(x)=-(4+2)^2-1\\f(x)=-37

According to AJ's graph for the value of x=-4 the function should be positive, however it is negative and for the value of x=4 the function should be positive and the function is negative

therefore

AJ made a mistake in the graph

8 0
3 years ago
270 concert tix were sold. Today 216 tix were sold. Find the percent change.
vfiekz [6]
270 - 216 = 54

54/270 x 100 = 20%

answer: 20% decrease


6 0
3 years ago
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