<span>Common Factors of 32 and 36
factors of 32 = 1, 2, 4, 8, 16 and 32
factors of 36 = 1, 2, 3, 4, 6, 9, 18, 36
So the common factors of 32 and 36 are 1, 2 and 4.
The greatest common factor is 4</span>
2 consecutive integers...x and x + 1
x + x + 1 < = 3
2x + 1 < = 3
2x < = 3 - 1
2x < = 2
x < = 1
x + 1 = 1 + 1 = 2.......the greatest possible value for the greatest integer is 2
36/60, now reduce.
9/15, reduce more
3/5, so 3.5 of the students chosen at random used a calculator for computation.
3=4m+ b
-1=3m+b
m=4
plug in to either equation,
3=16+ b
b=-13
Thus, C would be the answer.
First, find what one lightbulb costs.
9.85 / 5 = 1.97
Then multiply the product by 7.
1.97 * 7 = 13.79
Seven light bulbs will cost $13.79