Help please 0.3 [. ] 0.4 What is the decimal <,> or =

Explain how knowing that 5/8 = 0.625 helps you write the decimal for 4 5/8

tatyana61 [14]

When writing a decimal, the numbers to the left of the decimal are whole numbers greater then or equal to 1. The numbers to the right of the decimal are numbers less then 1.

if u know 5/8 = 0.625, then 4 5/8 = 4.625

4 0

3 years ago

Sammy bought 15.3 Liters of milk. She poured the milk equally into 5 bottles. There was 0.35 liters of milk left over. Calculate

Zanzabum

Answer:

The capacity of milk in 1 bottle is 2.99 liters

Step-by-step explanation:

Let us solve the question

∵ Sammy bought 15.3 liters of milk

∵ She poured the milk equally into 5 bottles

∵ There were 0.35 liters of milk leftover

→ At first, subtract the leftover from the quantity she bought to

find the capacity of the five bottles

∴ The capacity of the 5 bottles = 15.3 - 0.35

∴ The capacity of the 5 bottles = 14.95 liters

→ To find the capacity of each bottle divide the total capacity by 5

∴ The capacity in one bottle = 14.95 ÷ 5

∴ The capacity in one bottle = 2.99 liters

∴ The capacity of milk in 1 bottle is 2.99 liters

8 0

3 years ago

Find the equation of the circle with center at (3, -2) and radius of 3.

kvasek [131]

(x-3) *squared* + (y + 2) *squared* = 6

4 0

3 years ago

If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle

stira [4]

Answer:

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

Step-by-step explanation:

Given points end Points are p(-3,-2) and q( 1,6)

The distance of two points formula

P Q = $\sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2} }$

P Q = $\sqrt{1 - (-3)^{2} + ((6 -(-2))^{2} }$

P Q = $\sqrt{16+64} = \sqrt{80}$

The diameter 'd' = 2 r

2 r = √80

= $\sqrt{16 X 5}$

= $4 \sqrt{5}$

r = 2√5

Mid-point of two end points

$(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )$

= (-1 ,2)

Mid-point of two end points = center of the circle

(h,k) = (-1 , 2)

The equation of the circle

(x -h )² +(y-k)² = r²

(x -(-1) )² +(y-(2))² = (2(√5))²

x² + 2 x + 1 + y² - 4 y + 4 = 20

x² + 2 x + y² - 4 y = 20 -5

x² + 2 x + y² - 4 y = 15

Final answer:-

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

6 0

3 years ago

Aaaajsnsajdnjsadnjandja'

alekssr [168]

Answer:

wkkeek

Step-by-step explanation:

99992ndndnddke

4 0

3 years ago

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