Combinatorial Enumeration. That whole class was a rollercoaster ride of mind-blowing generating functions to prove crazy things. The exam had ridiculous questions like 'count the number of cactus trees with n vertices such that etc etc etc' and you'd do three pages of terrible terrible sums and algebra. Then your final answer would be something beautiful like n/2 and you'd breath a sigh of relief and thank the math gods.
Given:
The expression is

To find:
The equivalent expression.
Solution:
Distributive property of multiplication over addition is

Where, a, b and c are real numbers.
We have,

Using distributive property, we get


Therefore, the expression
is equivalent to the given expression.
Answer:
whats the question that is a statement
Step-by-step explanation:
If xy=0, assume that x and/or y=0
so we already gots factored
therfor
assume
3n-2=0 and 4n+1=0
solve
3n-2=0
3n=2
n=2/3
4n+1=0
4n=-1
n=-1/4
n=2/3 and/or -1/4
Answer:
A
Step-by-step explanation: