Line JK passes through points J(-4,-5) and K(-6, 3). If the equation of the line is written in slope-intercept form, y = mx + b,
1 answer:
Answer:
Line JK passes through points J(-4,-5) and K(-6, 3).
Line JK has form of y = mx + b
=> -5 = -4m + b
=> 3 = -6m + b
Subtract 2nd equation from 1st equation:
=> -8 = 2m
=> m = -4
Substitute back m = -4 into 1st equation:
=> -5 = -4(-4) + b
=> b = -21
Hope this helps!
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