Question

Line JK passes through points J(-4,-5) and K(-6, 3). If the equation of the line is written in slope-intercept form, y = mx + b,

Answer 1

Answer:

Line JK passes through points J(-4,-5) and K(-6, 3).

Line JK has form of y = mx + b

=> -5 = -4m + b

=>  3 = -6m + b

Subtract 2nd equation from 1st equation:

=> -8 = 2m

=> m = -4

Substitute back m = -4 into 1st equation:

=> -5 = -4(-4) + b

=> b = -21

Hope this helps!

:)