All categories

3 years ago

Line JK passes through points J(-4,-5) and K(-6, 3). If the equation of the line is written in slope-intercept form, y = mx + b,

Mathematics

1 answer:

Scilla [17]3 years ago

6 0

Answer:

Line JK passes through points J(-4,-5) and K(-6, 3).

Line JK has form of y = mx + b

=> -5 = -4m + b

=> 3 = -6m + b

Subtract 2nd equation from 1st equation:

=> -8 = 2m

=> m = -4

Substitute back m = -4 into 1st equation:

=> -5 = -4(-4) + b

=> b = -21

Hope this helps!

You might be interested in

What's the answer <br>c2+8c+7

lara [203]

Are you factoring or simplifying?

6 0

3 years ago

Read 2 more answers

When the sample size and sample standard deviation remain the same, a 99% confidence interval for a population mean, µ will be n

motikmotik

A 99% confidence interval will be wider compared to a 95% confidence interval. This is because while you don't know what the true value of mu is, you are more confident that the parameter is in the interval.

In essence, you are casting a wider net which leads to the higher level of confidence. Imagine if there was a 100 mile stretch of straight land, and somewhere on this line was a special rock that you are looking for. You would be 100% confident if you said "the rock is somewhere on that piece of land", and less confident the more you shrunk the interval.

5 0

3 years ago

Simplify the expression \[\frac{6}{\sqrt{36} + \sqrt{27}} + \frac{6}{\sqrt{27} + \sqrt{18}} + \frac{6}{\sqrt{18} + \sqrt{9}}.\]

Viktor [21]

Answer:

= 18 ( 3 + 2(\sqrt{3} + \sqrt{2} ))

Step-by-step explanation:

$6(\sqrt{36} +\sqrt{27}) + 6(\sqrt{27} +\sqrt{18}) + 6(\sqrt{18} + \sqrt{9} )\\= 6( {6} +\sqrt{9*3}) + 6( \sqrt{9*3} +\sqrt{9*2}) + 6(\sqrt{9*2} + 3 )\\= 6( {6} +3\sqrt{3}) + 6(3\sqrt{3} +3\sqrt{2}) + 6(3\sqrt{2} + 3 )\\=36 + 18\sqrt{3} + 18\sqrt{3} + 18\sqrt{2}+ 18\sqrt{2} + 18\\= 36+18 +18( \sqrt{3}+ \sqrt{3} +\sqrt{2} + \sqrt{2})\\= 54 + 18 (2\sqrt{3} +2\sqrt{2})\\=54 + 36\sqrt{3} + 36\sqrt{2}\\= 18 ( 3 + 2(\sqrt{3} + \sqrt{2} ))$

7 0

3 years ago

Pre-calc<br> Evaluate f(2) using substitution:<br> f(x) = 2x^3 – 3x^2– 18x-8

krek1111 [17]

Answer:

f(2) = -40

Step-by-step explanation:

Just substitute x=2 into the function:

f(x) = 2x³ - 3x² - 18x - 8

f(2) = 2(2)³ - 3(2)² - 18(2) - 8

f(2) = 2(8) - 3(4) - 36 - 8

f(2) = 16 - 12 - 44

f(2) = 4 - 44

f(2) = -40

8 0

2 years ago

A rectangle has length that is 5 less than 2 times the width. Write an expression for the area of the rectangle.

a_sh-v [17]

We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula:

$A=Lw$

We can use the relationship given in the problem, that is, its length being five less two times its width, that is:

$L=5-2w$

Replacing in the formula for the area we get:

$A=(5-2w)w$

Now we use the distributive law:

$A=5w-2w^2$

7 0

1 year ago