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3 years ago

Line JK passes through points J(-4,-5) and K(-6, 3). If the equation of the line is written in slope-intercept form, y = mx + b,

Mathematics

1 answer:

Scilla [17]3 years ago

6 0

Answer:

Line JK passes through points J(-4,-5) and K(-6, 3).

Line JK has form of y = mx + b

=> -5 = -4m + b

=> 3 = -6m + b

Subtract 2nd equation from 1st equation:

=> -8 = 2m

=> m = -4

Substitute back m = -4 into 1st equation:

=> -5 = -4(-4) + b

=> b = -21

Hope this helps!

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2g + h =2 g -h= -5 find g and h step by step explanation

wel

Answer:

Step-by-step explanation:

2g + h = 2 --------------(I)

g - h = -5------------(II)

g = -5 + h

Plugin g = -5 + h in equation (I)

2(-5 + h) + h = 2 {Distributive property:a(b+c) = a*b +a*c}

(-5)*2 + h *2 + h= 2

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